Correct answer: Qa11...N:d3[a]/Ne4 2.Qb3#[A] 1...N:d7/[б]/ 2.Qf3#[Б] 1...Ne6/Nb3/Nb7/Na4/Na6 2.Qf3#[Б]/Qb3#[A] 1.Rc8? (2.R:c5#) 1...N