Correct answer: Rb51...Kd8 2.Ra8# 1...c5 2.Ra8#/Qa8# 1.Ra7?? (2.Qe8#) 1...Kd8 2.Ra8# but 1...Kb8! 1.Rb5! (2.Qe8#) 1...Kd8 2.Rb8# 1
