Correct answer: Qb71...Rg5/Rg4/Rg3[a]/Rg2/[б]//Rg1/Rg7/Rg8/Rf6/Rh6 2.Qd3# 1.Rfd3? (2.Ne3#[A]) 1...Rg3[a] 2.Nd2#[Б] but 1...Nc3[c]!
