Correct answer: Qh61...e2[a] 2.Qg1#[A] 1...c:b4/[б]//c4[c] 2.B:b6#[Б] 1...d:e4[d] 2.Qd7#[C] 1.B:b6[Б]? (2.B:c5#) but 1...d:e4[d]! 1.Qg1[A]? (2.Qd1#) but 1...c:b4/[б]/! 1.Q
