Correct answer: Qc61...Nb1[a]/Nc2[a] 2.Qe2#[A] 1...Nb5/[б]/ 2.Qc8#[Б] 1.Qe2+[A]?? 1...Nc4 2.Q:c4#[C] but 1...Nb5/[б]/! 1.Qa4?? zz 1...Nb1[a]/N
