Correct answer: Qc81...Kf3[a] 2.Nce5#[A] 1...Kd5/[б]/ 2.Nf4#[Б] 1.Qa6? (2.Qd3#) 1...Kf3[a] 2.Qe2#[C] 1...Kd5/[б]/ 2.Qc4#[D] but 1...b5! 1.Kb5?? zz
