Correct answer: Qc51...Bd2[a] 2.B:d2# 1.Qc3? (2.Q:e5#[A]) 1...Bd2[a]/B:c1 2.Qf3# but 1...d4/[б]/! 1.Qc2? (2.Qf2#[Б]) 1...d4/[б]/ 2.Q:e4# 1...K:f5
