Correct answer: Qh61...Ne4[a] 2.Qf7# 1...Ne6/[б]/ 2.Qf3#[Б] 1...Nf4/Bh4/Be5 2.Re5#[A] 1...Nf3/Nf7 2.Q:f3#[Б]/Qf7# 1.Qg4? (2.Bd7#) 1...
