Correct answer: Qg51...Rd7[a]/Rd8[a]/Rc6[a] 2.Qc6#[Б] 1...Qa6/Qa5/Qa4/Qa2/Qa1/Qa8/Qb7/Qc5/Qb8/Rb6/[б]/ 2.Qc5#[A] 1...Rc4[c] 2.Q
