Correct answer: Nc41...Nc4[a]/Nd1/[б]//Nd3 2.R4e5#[A] 1...Bg1 2.Qh5#[Б] 1.Qf1? (2.Qf5#[C]) 1...Nc4[a] 2.Qd3#/Q:c4# 1...Nd3 2.Q:d3# but 1...g
