Correct answer: Bc11...Rc1[a]/Rb2+ 2.Bb2#[A] 1...R:c3+/[б]/ 2.Q:c3#[Б] 1...Ra2/R:d2 2.Qb1# 1.Qf1? zz 1...Rc1[a] 2.Bb2#[A] 1...R:c3+/[б]/ 2.N
