Correct answer: Qd71...c3 2.Qb5# 1.Qd8? (2.Be5#/B:e7#) 1...N:f4[a] 2.B:f4#[A] 1...B:c5/[б]/ 2.B:c5#[Б] 1...e:d6[c] 2.Q:d6#[C] 1...B:c7 2.B:c7# but
