Correct answer: Qg41...K:e5[a]/Be6[c] 2.Ne6#[A] 1...Kc5/[б]/ 2.Qd6#[Б] 1...B:a4 2.Qd6#[Б]/Ne6#[A] 1.Ng4? zz 1...Kc5/[б]/ 2.Qd6#[Б] 1...Bc4[d]/B<