Correct answer: Qc61...Bb4[a]/Bb6 2.R:b4#[A] 1...Ne2/Ne6/Nf3/Nf5/N:c2/[б]//Nc6[c] 2.B:b5#[Б] 1...Nc3[d]/Na3[d]/Na7[e] 2.Ra3#[C] 1...N:b3 2.