Correct answer: Qc21...Kd4[a]/b4[a]/c2 2.Qd3#[A] 1.Q:c6? zz 1...Kd4[a]/b4[a]/c2 2.Q:d5#[C] 1...Kb4/[б]//d4/[б]/ 2.Q:b5#[Б] but 1...g:f4! 1.Ka5?? (2.Qd3#[A]) but 1.
