Correct answer: Qd31...Be4[a] 2.K:e4#[A] 1...Bg2/[б]//Bh1/[б]//Bc6[e] 2.Qg4#[Б] 1...Be6[c]/Ba2[d] 2.Qa4#[C] 1...Bc4 2.K:c4# 1.Qh5? (2.Q:d5#) 1.
