Correct answer: Be51...Be1[a]/Be3/Bf4/[б]//Bg5/Bh6/Bc1 2.Q:e1#[A] 1...Nf4[c]/Nd4/Nc1/Nc3 2.Q:g1#[Б] 1...Ng3 2.Ng4#/Bd4#/Q:g1#[Б]