Correct answer: Bf11...Ng3[a] 2.Bg5#[A] 1...Ne3/[б]/ 2.Be5#[Б] 1...e3 2.Bh4#/R:g4# 1...g:h3 2.Bd4#[C] 1...g3 2.Bg5#[A]/Bd4#[C] 1.Nf5? (2.Bg5#[A]/Be5#[Б])