Correct answer: N:d31...Nh2[a]/Nh6[a]/Nf2[a]/Nf6/[б]//Ne3/[б]//Ne5[a] 2.Ne3#[A] 1...Bd1[c]/Bb1[d]/Bb3[e]/Ba4[c] 2.Nd2#[Б] 1...e3[f] 2.Bd5#[C] 1.R