Correct answer: Bd81...f2 2.Qh1# 1...Nb6/Ba5 2.Na5# 1...Bd8 2.N:d8# 1...Bb8 2.Nd8#/Na5# 1.Qc3? (2.Q:f3#[A]) 1...Nb6 2.Na5# but 1...B:d
