Correct answer: Nd21.Nd6? (2.Qf7#[A]) but 1...Kd5[a]! 1.Nb6? (2.Qd7#[Б]) but 1...Kf5/[б]/! 1.Nd2! zz 1...Kd5[a] 2.Qd7#[Б] 1...Kf5/[б]/ 2.Qf7#[A
