Correct answer: Qh81...Ke4 2.Bd5# 1.Kb5? (2.Qa8#[A]) 1...Ke4 2.Bd5# but 1...Ba7[a]! 1.Bh4? (2.Qh1#[Б]) 1...Ke4 2.Bd5# but 1...Nf1/[б]/! 1