Correct answer: Bd51...B:b6/a:b6 2.Qc4# 1.Be8?? (2.Qd4#/Qb5#) 1...K:b6 2.Qc6# 1...Bb4 2.Qb5#/Qc6# 1...a6 2.Qd4# but 1...d5! 1.Bd5! (2.Q<