Correct answer: Bc11...Bc3[a] 2.Qf4#[A] 1...f:e5/[б]/ 2.Qd2#[Б] 1...Bb2 2.B:b2# 1.Bb3? (2.Qd2#[Б]) 1...Bc3[a] 2.Qf4#[A] 1...Kc3[d] 2.Qe3#[C] but 1...