Correct answer: Qc61...Bg8[a]/Bd5[c]/Bc4[a]/Bb3[d]/Ba2[a] 2.Bf6#[A] 1...Be6/[б]/ 2.Qd4#[Б] 1...d2[e] 2.Re4#[C] 1...Be8 2.Bf6#[A]/R:e8# 1.K:a4? zz
