Correct answer: Rc71...Ke5[a]/Qf7/Qe7/Qh7 2.Q:d4#[A] 1...Qg4/Qc7/[б]//Qh8/Qf6 2.Qc7#[Б] 1...e5 2.Qc6# 1...Bc4 2.Nd3# 1...Qg6/Qg5/Q
