Correct answer: Qe41...Rc7[a]/Bc7 2.Qd1#[A] 1.Rd2+[Б]?? 1...Kc7 2.Be5#/Bd8# but 1...Ke6! 1.Qb6? (2.Q:c6#) 1...Bd7/[б]/ 2.Be7#[C] 1...B