Correct answer: Qe71...Kd4[a] 2.Qc4#[A] 1...Kf4/[б]/ 2.Qg4#[Б] 1.Kd2?? zz 1...Kd4[a] 2.Qd5#/Qc4#[A] 1...Kf4/[б]/ 2.Qg4#[Б] but 1...Kf3! 1.Kf2?