Correct answer: Nc51...Nc3[a] 2.Ne6#[A] 1...Nd6/[б]/ 2.Rd5#[Б] 1...Na7 2.Rd5#[Б]/Ne6#[A] 1...d5 2.Ne6#[A]/N:b5#/Q:d5# 1.Qf6[C]? (2.e6#[D]) but 1...f:e2! 1.
