Correct answer: Nd41...g5[a] 2.Nf5#[A] 1...d2/[б]/ 2.Bd4#[Б] 1...Nf3[c]/Nf7[d]/Ng4[d]/Ned7[d]/Nc4[e]/Nc6[d] 2.Ng4#[C] 1...Ncd7[f]/Ne4[f]/N:e6[f]/Nb3[g]/<