Correct answer: Qh71.Qf5? (2.Qe5#) 1...Nc6[a] 2.R5:c6#[C] 1...Rd7/[б]/ 2.R:d7#[A] 1...B:c5[c] 2.Q:c5#[Б] 1...Bd5[d] 2.Q:d5#[D] but 1...Bd4! 1.Q