Correct answer: Nc71...b1N[a] 2.Ne3#[A] 1...d1N/[б]/ 2.Nd2#[Б] 1...Bg7/Bh6/Bd6 2.Nd6# 1...R:f1+ 2.B:f1# 1...b1B/d1B 2.Ne3#[A]/N:d2#[Б] 1...d4
