Correct answer: Rd:d51...Ne3[a]/Nf2/Nc3/Nb2 2.Nc3#[A]/R:e3#[Б] 1...Nc1/Nc5/Nd2/Nd4/[б]//Na1/Na5 2.Nd2#[C]/Rd4#[D] 1...g3 2.e:f3# 1...B:d3 2