Correct answer: Qa11...Qf4+[a] 2.K:f4#[A] 1...Qe3+/[б]/ 2.K:e3#[Б] 1...h3 2.Kg3# 1...Qh5/Qh7/Qh8/Qg6/Qg7/Qf8 2.Kf4#[A]/Ke3#[Б] 1.Qd1? (2.B