Correct answer: Qc71...e:d5[a] 2.Q:d5#[A] 1...g4 2.Bf4# 1.d7[Б]? zz 1...e:d5[a] 2.Q:d5#[A] 1...Nf2[c]/Ng3[c]/Nd2[c] 2.Qc7#[C]/d6# 1...N:f6[d]/N:c3[e]/Nc5[f] 2
