Correct answer: Qa51...B:e2[a] 2.Q:e2#[A] 1...Nc4/[б]//Nd3[c] 2.Nd3#[Б] 1...Ng3[d]/Ng7[e]/Nh4[e]/Nh6[e]/Ne3[f]/Ne7[e]/Nd4[g]/Nd6[e] 2.Q:g3#[C]