Correct answer: Nb51...B:d8[a] 2.c:d8N#[Б] 1...Nd3/Nd7/[б]//Ne4/[б]//Nb3/Na6 2.Bd7#[C] 1...Be5 2.f5#[A] 1...d3 2.Re4# 1.R:c5+? 1...Bd5 2.c8Q#/c
