Correct answer: Q:d61...Kf5[a]/Rh4/Rh3/[б]//Rh2/Rh1 2.Qh7#[A] 1...e:f4[c] 2.Ng5#[C] 1...Nf3 2.Bc2#[Б] 1.Qb5? (2.Qd3#) 1...Kf5[a] 2.Bc2#[Б] 1
