Correct answer: Nfe81...Qd5[a]/Qd6/[б]//Qd8/[б]//Qg4[f] 2.Ng4#[A] 1...Qd7[c]/Qe4[d]/Qf4[e]/Qh4[g] 2.N:d7#[Б] 1...Q:c3+ 2.B:c3# 1.Qf1? (2.Qf5#/c