Correct answer: Rf71...d2 2.Qc4#[A] 1.Ra6? (2.Qc6#[Б]) but 1...Ke4[a]! 1.Ra4? (2.Qc4#[A]) but 1...Ke6/[б]/! 1.Nh4? zz 1...Ke4[a]/d2 2.Qc4#[A] 1...K<