Correct answer: Qf11...Kd4[a] 2.R:d3#[A]/Qe5#[Б]/Q:d3#[C] 1...Kb4/[б]/ 2.Qc5# 1.Ra1? zz 1...Kd4[a] 2.R:d3#[A] 1...Kb4/[б]/ 2.Qa5#[D] 1...Kd2[c]