Correct answer: Rd31...Bd2[a]/Rd3/Re1[a]/Rf1[a]/Rg1[c]/Rh1[a] 2.Nd3#[A] 1...B:f4/[б]/ 2.Q:f4#[Б] 1...Rd4/d4[d] 2.Qe7#[C] 1...Be3/Bb2/Ba3/Rd
