Correct answer: Q:b71...Re7[a] 2.Bc3#[A] 1...R:e6/[б]/ 2.Qf2#[Б] 1...Bd1/Bc4/B:e6[c]/Ba2/Ba4 2.Rf3#[C] 1.Qc7? (2.Qf7#/Qe5#) 1...Re7[a]/