Correct answer: Qd51...Kc8+[a]/Ne6[h] 2.Q:e8#[A] 1...Bf7/[б]//Bg6[c]/Bh5[d] 2.Qc8#[Б] 1...Nh3[e]/Nh7[e]/Nf3[e]/Nf7[f]/Ne4[g] 2.Q:g4#[C] 1.Rh7?