Correct answer: Nd21...Ne2[a] 2.Rd3#[Б] 1...B:e4 2.R:e4#/Q:e4#/Bf4#[A] 1...Ba4 2.Bf4#[A] 1.Bf1? (2.Rd3#[Б]) 1...Bb5/[б]/ 2.Bf4#[A] 1...B:e4
