Correct answer: Qf61...d4[a] 2.Be7#[A] 1...e:d2/[б]/ 2.B:d2#[Б] 1.Bf6? (2.Bc3#) 1...d4[a] 2.Be7#[A] 1...e:d2/[б]/ 2.Q:d2#[C] but 1...a2! 1.Qh4+?? 1...d4[a] 2.Be7#[A]
