Correct answer: Qa11...Ke4[a] 2.Qa8#[A] 1.Rh1? zz 1...K:g2/[б]/ 2.Qa8#[A] 1...Kg4[c]/Ke2[d] 2.Qh5#[C] but 1...Ke4[a]! 1.Rf5+? 1...Ke4[a] 2.Q