Correct answer: Nb51...R:e4[a] 2.Qg5#[A] 1...B:e4/[б]/ 2.Qg3#[D] 1...c5 2.Rd5# 1...N:g4 2.N:g4#[Б] 1...Ng6/Nf7 2.Nf7#[C] 1.Bf3? (2.Qg5#[A]) 1...N