Correct answer: Qh41.Qh3? zz 1...Kb1[c]/Bb3[a]/Bd5[e]/Be6[f]/Bf7[c]/Bg8[c] 2.Qf1#[Б] 1...Bb1/[б]/ 2.Qc3#[C] but 1...Bc4[d]! 1.Qg7? zz 1...K