Correct answer: Ba21...B:d2+[a] 2.R:d2#[Б] 1...Bf4/Bg5/Bh6/Bc5+/[б]/ 2.Rc5#[A] 1...Ke4 2.Qf5#/Rc5#[A] 1...d6 2.Qf5# 1.Nc5[C]? (2.Ba2#[D]) 1...<
